Each element is represented by an SDR. The SDR is 2048 bits long, with 40 active at a time (each bit here represents one minicolumn). Each noise element is represented by 40 random minicolumns chosen from the 2048 possible. The noise elements are not the same - they are completely different for each timestep. There are a finite number of noise elements, but the number is astronomically large.

# Why Neurons Have Thousands Of Synapses, A Theory Of Sequence Memory In Neocortex

**sheiser1**#63

I think that if a sequence element is random then it couldnât have been correctly predicted because its not part of a pattern (a recurring sub-sequence). Imagine the case where 100% of the sequence elements were generated randomly. The TM would ultimately learn nothing over time because all the transitions that it did learn were noise and therefore didnât repeat, so the synaptic permanences representing those transitions would never be reinforced.

A TM with no reinforced paths is a TM that predicts nothing, for 0% prediction accuracy. In summary, the TM can only predict sequence elements it has detected within a pattern, and random/noise elements by definition arenât.

**nbro**#64

I partially agree with your reasoning, but thereâs a clear repeating pattern in the data, that is

sequence, noise, sequence, noise, sequence, noise, etc

where each sequence has the same number of elements and all noises have the same length. Furthermore, a sequence may repeat.

Here, the confusion/ambiguity is due to the way one defines the prediction accuracy. If one defines the prediction accuracy as the percentage of correctly predicted one-step ahead next input element (either belonging to the sequence or to the noise), then you reasoning makes sense, but the dataset was defined in such a structured way that Iâm not seeing why the 50% prediction accuracy mathematically holdsâŚ

**sheiser1**#65

I think this is effectively what they mean by ''prediction accuracy. And yes the âseq., noise, seq., noiseâŚâ means that there is repetition to learn from, though only during the seq parts. The other 50% are bouts of noise, so since the TM doesnât have anything solid to learn from these it wont predict anything during these periods - which would cap the max overall prediction accuracy at 50%. Its like if you were reading something but half of the words were noise (illegible gibberish), the most you could actually make sense of would be the 50% that were real words right?

Btw I also think this demonstrates a great strength of the TM, in that it can learn so aggressively but not be prone to overfitting, since all the noisy transitions it learned at first are washed out since they donât repeat.

**nbro**#66

In the section **Network Capacity and Generalization**, itâs written

The network only learns transitions between inputs. Therefore, the capacity of a network is measured by how many transitions a given network can store. This can be calculated as the product of the expected duty cycle of an individual neuron (cells per column/column sparsity) times the number of patterns each neuron can recognize on its basal dendrites.

A few questions (if you have time to answer @subutai and @jhawkins):

- What exactly do we mean in this context by âexpected duty cycle of an individual neuronâ?
- Why is the expected duty cycle calculated as âcells per column/column sparsityâ?
- Why is the capacity of a network (i.e. how many transitions a given network can store) calculated as âthe product of the expected duty cycle of an individual neuron
*times*the number of patterns each neuron can recognize on its basal dendrites.â?

**rhyolight**#67

You are right that this passage is confusing. The equation for computing capacity is correct but Iâm not sure what we meant by duty cycle there. We didnât really formally define duty cycle for the TM.

If everything is equal, you would expect the average firing rate of a neuron in the TM to be: pct sparsity / number of cells per column. For example, with 2% sparsity and one cell per column, each cell would be active with probability 0.02. With 32 cells per column, each cell would be active with probability 0.000625.

If we are going to call something a âduty cycleâ, then it should be 1 divided by (cells per column/sparsity). As written the answer is 1600, but the duty cycle of a cell is actually 1/1600. Although strictly speaking the text is not correct, I donât think this deserves a correction. The way it was written was to tell the reader what numbers impact the capacity of the network. The answer, 320,000 transitions, is correct. I can see how some readers would be confused, but it is too minor to edit at this point.